×
Please submit new Bug Reports on GitHub: github.com/Jensen-Technologies/component-creator-issues/issues
Show on list view no longer working correctly
alex
New Member
Posts: 2
7 lata 11 miesiąc temu #1470
przez alex
Show on list view no longer working correctly was created by alex
I have a field J_SQL
It is a select of virtuemart products.
On the list view it always has shown the "selected" product. ie the value in the database.
Now, after my last rebuild the list view shows all the same product , which is the "lowest id" in the virtuemart product database.
It is a select of virtuemart products.
On the list view it always has shown the "selected" product. ie the value in the database.
Now, after my last rebuild the list view shows all the same product , which is the "lowest id" in the virtuemart product database.
Proszę Zaloguj lub Zarejestruj się, aby dołączyć do konwersacji.
Chris
New Member
Posts: 3
7 lata 10 miesiąc temu #1484
przez Chris
Replied by Chris on topic Show on list view no longer working correctly
I see same problem. I checked my database, data is saving correctly, but showing incorrectly on admin list view.
Proszę Zaloguj lub Zarejestruj się, aby dołączyć do konwersacji.
Chris
New Member
Posts: 3
7 lata 10 miesiąc temu #1485
przez Chris
Replied by Chris on topic Show on list view no longer working correctly
I was able to adjust the query in the list model, adding a left join, grabbing the correct data. Then I edited the view file, showing the "name" rather than the "id" of the field in question. This challenged my SQL skills, but solved the problem.
Proszę Zaloguj lub Zarejestruj się, aby dołączyć do konwersacji.
alex
New Member
Posts: 2
7 lata 10 miesiąc temu #1487
przez alex
Replied by alex on topic Show on list view no longer working correctly
so how did you solve this?
can you post it here?
can you post it here?
Proszę Zaloguj lub Zarejestruj się, aby dołączyć do konwersacji.
Chris
New Member
Posts: 3
7 lata 10 miesiąc temu #1490
przez Chris
Replied by Chris on topic Show on list view no longer working correctly
Alex, Something like this...
let's say you have "items" and "parents". You want to show a list of items with the correct parent name.
Modify the query in the model, adding #__parents.name AS parentName in the select().
Modify the query further, adding a LEFT JOIN ON item.parent_id = #__parents.id.
Notice the parentName alias, this is important. I think I also aliased the table name simply to reduce typing, not important.
Now go into your view. Instead of displaying parent_id, display parentName. You probably don't have a "parentName" column in your #__parents table, that's ok, we created one on the fly with our alias.
I had to brush up on MySql joins as well as the JDatabase query() object.
As always for testing, in the model, before "return $query", add var_dump( $query->__toString() ); die; so that you can monitor the query. Cut and paste into PHPMyAdmin to test.
As an alternative, blow away the query found in the model, and write your own, might be simpler. Just remember to join "name" from the "parents" table as an alias.
That's as specific as I can explain, hope it helps.
let's say you have "items" and "parents". You want to show a list of items with the correct parent name.
Modify the query in the model, adding #__parents.name AS parentName in the select().
Modify the query further, adding a LEFT JOIN ON item.parent_id = #__parents.id.
Notice the parentName alias, this is important. I think I also aliased the table name simply to reduce typing, not important.
Now go into your view. Instead of displaying parent_id, display parentName. You probably don't have a "parentName" column in your #__parents table, that's ok, we created one on the fly with our alias.
I had to brush up on MySql joins as well as the JDatabase query() object.
As always for testing, in the model, before "return $query", add var_dump( $query->__toString() ); die; so that you can monitor the query. Cut and paste into PHPMyAdmin to test.
As an alternative, blow away the query found in the model, and write your own, might be simpler. Just remember to join "name" from the "parents" table as an alias.
That's as specific as I can explain, hope it helps.
Za tę wiadomość podziękował(a): Andres Maeso
Proszę Zaloguj lub Zarejestruj się, aby dołączyć do konwersacji.
Czas generowania strony: 0.053 s.