×
Please submit new Bug Reports on GitHub: github.com/Jensen-Technologies/component-creator-issues/issues
Show on list view no longer working correctly
alex
New Member
Posts: 2
7 år 11 måneder siden #1470
af alex
Show on list view no longer working correctly blev oprettet af alex
I have a field J_SQL
It is a select of virtuemart products.
On the list view it always has shown the "selected" product. ie the value in the database.
Now, after my last rebuild the list view shows all the same product , which is the "lowest id" in the virtuemart product database.
It is a select of virtuemart products.
On the list view it always has shown the "selected" product. ie the value in the database.
Now, after my last rebuild the list view shows all the same product , which is the "lowest id" in the virtuemart product database.
Venligst Log på eller Opret en konto for at deltage i samtalen
Chris
New Member
Posts: 3
7 år 10 måneder siden #1484
af Chris
Besvaret af Chris på emne Show on list view no longer working correctly
I see same problem. I checked my database, data is saving correctly, but showing incorrectly on admin list view.
Venligst Log på eller Opret en konto for at deltage i samtalen
Chris
New Member
Posts: 3
7 år 10 måneder siden #1485
af Chris
Besvaret af Chris på emne Show on list view no longer working correctly
I was able to adjust the query in the list model, adding a left join, grabbing the correct data. Then I edited the view file, showing the "name" rather than the "id" of the field in question. This challenged my SQL skills, but solved the problem.
Venligst Log på eller Opret en konto for at deltage i samtalen
alex
New Member
Posts: 2
7 år 10 måneder siden #1487
af alex
Besvaret af alex på emne Show on list view no longer working correctly
so how did you solve this?
can you post it here?
can you post it here?
Venligst Log på eller Opret en konto for at deltage i samtalen
Chris
New Member
Posts: 3
7 år 10 måneder siden #1490
af Chris
Besvaret af Chris på emne Show on list view no longer working correctly
Alex, Something like this...
let's say you have "items" and "parents". You want to show a list of items with the correct parent name.
Modify the query in the model, adding #__parents.name AS parentName in the select().
Modify the query further, adding a LEFT JOIN ON item.parent_id = #__parents.id.
Notice the parentName alias, this is important. I think I also aliased the table name simply to reduce typing, not important.
Now go into your view. Instead of displaying parent_id, display parentName. You probably don't have a "parentName" column in your #__parents table, that's ok, we created one on the fly with our alias.
I had to brush up on MySql joins as well as the JDatabase query() object.
As always for testing, in the model, before "return $query", add var_dump( $query->__toString() ); die; so that you can monitor the query. Cut and paste into PHPMyAdmin to test.
As an alternative, blow away the query found in the model, and write your own, might be simpler. Just remember to join "name" from the "parents" table as an alias.
That's as specific as I can explain, hope it helps.
let's say you have "items" and "parents". You want to show a list of items with the correct parent name.
Modify the query in the model, adding #__parents.name AS parentName in the select().
Modify the query further, adding a LEFT JOIN ON item.parent_id = #__parents.id.
Notice the parentName alias, this is important. I think I also aliased the table name simply to reduce typing, not important.
Now go into your view. Instead of displaying parent_id, display parentName. You probably don't have a "parentName" column in your #__parents table, that's ok, we created one on the fly with our alias.
I had to brush up on MySql joins as well as the JDatabase query() object.
As always for testing, in the model, before "return $query", add var_dump( $query->__toString() ); die; so that you can monitor the query. Cut and paste into PHPMyAdmin to test.
As an alternative, blow away the query found in the model, and write your own, might be simpler. Just remember to join "name" from the "parents" table as an alias.
That's as specific as I can explain, hope it helps.
Følgende bruger(e) sagde tak: Andres Maeso
Venligst Log på eller Opret en konto for at deltage i samtalen
Tid til at oprette siden: 0.093 sekunder